In other words, only the line breaks located between two data lines It will replace any line-break, not preceded and not followed with an equal sign =. Only, the second alternative have changed (?Move back the caret back to the top of the file.
If the second alternative occurs, the unique line-break must be replaced with a simple space \x20Īhrrrrrhh ! You’re perfectly right, : my regex does not work, if no extra blank lines exist :-(( Insert a space all lines will now be space-padded out to the length of the caret column. If group 1 exists, all the consecutive line breaks are replaced with an unique line-break \1 In the replacement regex, we’re using a conditional replacement syntax (?#. \R the unique line-break, at end of the various lines (\R) which tries to match a range of, at least, 2 consecutive line-breaks, and stores current line-break form is group 1 The search regex contains 2 alternatives, separated with the alternation symbol | Note that the first blank line, only, is kept ! You should get the expected result, below Country: us || Suscriptions: Credits: Country: eu || Suscriptions: Credits: Country: es || Suscriptions: Credits: NO Select the Regular expression search mode So assuming the text below us || Suscriptions: I’m afraid, that the option Edit > Blank Operations > EOL to Space remove too many line-breaks !īut with the regex S/R, below, it does the job, correctly and, in addition, it deletes all possible unnecessary line-breaks, too -))
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